Database Design-Section 9 Quiz
Test: Section 9 Quiz
Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.
Section 9 Quiz
(Answer all questions in this section)
1. The explanation below is an example of which constraint type?
A column must contain only values consistent with the defined data format of the column Mark for Review
(1) Points
Entity integrity
Column integrity (*)
Referential integrity
User-defined integrity
Correct Correct
2. Identify all of the incorrect statements that complete this sentence: A primary key is...(Choose three) Mark for Review
(1) Points
(Choose all correct answers)
One or more columns in a table that uniquely identifies each row in that table.
Only one column that must be null. (*)
A single column that uniquely identifies each column in a table. (*)
A set of columns in one table that uniquely identifies each row in another table. (*)
Incorrect Incorrect. Refer to Section 9 Lesson 1.
3. A table does not have to have a primary key. True or False? Mark for Review
(1) Points
True (*)
False
Correct Correct
4. A foreign key always refers to a primary key in the same table. True or False? Mark for Review
(1) Points
True
False (*)
Correct Correct
5. When translating an arc relationship to a physical design, you must turn the arc relationships into foreign keys. What additional step must you take with the created foreign keys to ensure the exclusivity principle of arc relationships? (Assume that you are implementing an Exclusive Design) (Choose Two) Mark for Review
(1) Points
(Choose all correct answers)
Make all relationships mandatory
Make all relationships optional (*)
Create an additional check constraint to verify that one foreign key is populated and the others are not (*)
All the above
Correct Correct
Page 1 of 3 Next Summary
Test: Section 9 Quiz
Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.
Section 9 Quiz
(Answer all questions in this section)
6. When mapping supertypes, relationships at the supertype level transform as usual. Relationships at the subtype level are implemented as foreign keys, but the foreign key columns all become optional. True or False? Mark for Review
(1) Points
True (*)
False
Correct Correct
7. An "Arc Implementation" can be done just like any other Relationship - you simply add the required Foreign Keys. True or False? Mark for Review
(1) Points
True
False (*)
Incorrect Incorrect. Refer to Section 9 Lesson 4.
8. In a physical model, many to many relationships are resolved via a structure called a(n): ________________ Mark for Review
(1) Points
Intersection Table
Subtype
Intersection Entity (*)
Supertype
Incorrect Incorrect. Refer to Section 9 Lesson 3.
9. One-to-Many Optional to Mandatory becomes a _______________ on the Master table. Mark for Review
(1) Points
Unique Key
Optional Foreign Key (*)
Mandatory Foreign Key
Primary Key
Incorrect Incorrect. Refer to Section 9 Lesson 3.
10. It is possible to implement non-transferability via a simple Foreign Key Relationship. True or False? Mark for Review
(1) Points
True
False (*)
Incorrect Incorrect. Refer to Section 9 Lesson 3.
Previous Page 2 of 3 Next Summary
Test: Section 9 Quiz
Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.
Section 9 Quiz
(Answer all questions in this section)
11. An Arc is transformed to the physical model by adding a foeign Key for every relationship in the Arc. True or False? Mark for Review
(1) Points
True (*)
False
Correct Correct
12. The conceptual model is transformed into a physical model. The physical implementation will be a relational database. True or False? Mark for Review
(1) Points
True (*)
False
Correct Correct
13. The transformation from an ER diagram to a physical design involves changing terminology. Entities in the ER diagram become __________ : Mark for Review
(1) Points
Columns
Tables (*)
Unique Keys
Foreign Keys
Incorrect Incorrect. Refer to Section 9 Lesson 2.
14. In a physical data model, an attribute becomes a _____________. Mark for Review
(1) Points
Foreign Key
Constraint
Column (*)
Table
Incorrect Incorrect. Refer to Section 9 Lesson 2.
15. In a physical data model, a relationship is represented as a: Mark for Review
(1) Points
Column
Foreign Key (*)
Unique Identifier
Primary Key
Incorrect Incorrect. Refer to Section 9 Lesson 2.
Previous Page 3 of 3 Summary
Test: Section 9 Quiz
Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.
Section 9 Quiz
(Answer all questions in this section)
1. A table does not have to have a primary key. True or False? Mark for Review
(1) Points
True (*)
False
Correct Correct
2. Identify all of the correct statements that complete this sentence: A primary key is: (Choose Three) Mark for Review
(1) Points
(Choose all correct answers)
A set of columns that uniquely identifies each row in a table (*)
A single column that uniquely identifies each row in a table (*)
A set of columns and keys in a single table that uniquely identifies each row in a single table (*)
Only one column that cannot be null
Correct Correct
3. The explanation below is an example of which constraint type?
If the value in the balance column of the ACCOUNTS table is below 100, we must send a letter to the account owner which will require extra programming to enforce. Mark for Review
(1) Points
User-defined integrity (*)
Entity integrity
Referential integrity
Column integrity
Incorrect Incorrect. Refer to Section 9 Lesson 1.
4. The explanation below is an example of which constraint type?
A column must contain only values consistent with the defined data format of the column Mark for Review
(1) Points
Entity integrity
Column integrity (*)
Referential integrity
User-defined integrity
Correct Correct
5. One-to-One relationships are transformed into Foreign Keys in the tables created at either end of that relationship. True or False? Mark for Review
(1) Points
True
False (*)
Correct Correct
Page 1 of 3 Next Summary
Test: Section 9 Quiz
Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.
Section 9 Quiz
(Answer all questions in this section)
6. To resolve a many to many relationship in a physical model you create a(n) ___________________? Mark for Review
(1) Points
Two tables with Foreign key constraints between them
Unique key constraints
Intersection entity
Intersection table (*)
Incorrect Incorrect. Refer to Section 9 Lesson 3.
7. It is possible to implement non-transferability via a simple Foreign Key Relationship. True or False? Mark for Review
(1) Points
True
False (*)
Correct Correct
8. The Oracle Database can implement a many to many relationship. You simply create two foreign keys between the two tables. True or False? Mark for Review
(1) Points
True
False (*)
Incorrect Incorrect. Refer to Section 9 Lesson 3.
9. Why would this table name NOT work in an Oracle database? this_year_end+next_year Mark for Review
(1) Points
Table names must begin with an alphabetic character.
It is too long.
The Plus sign + is not allowed in object names. (*)
None of the above.
Incorrect Incorrect. Refer to Section 9 Lesson 2.
10. In a physical data model, a relationship is represented as a combination of: (Choose Two) Mark for Review
(1) Points
(Choose all correct answers)
Column
Check Constraint or Unique Key
Primary Key or Unique Key (*)
Foreign Key (*)
Incorrect Incorrect. Refer to Section 9 Lesson 2.
Previous Page 2 of 3 Next Summary
Test: Section 9 Quiz
Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.
Section 9 Quiz
(Answer all questions in this section)
11. The conceptual model is transformed into a physical model. The physical implementation will be a relational database. True or False? Mark for Review
(1) Points
True (*)
False
Correct Correct
12. In a physical data model, an attribute becomes a _____________. Mark for Review
(1) Points
Constraint
Table
Column (*)
Foreign Key
Correct Correct
13. When mapping supertypes, relationships at the supertype level transform as usual. Relationships at subtype level are implemented as foreign keys, but the foreign key columns all become mandatory. True or False? Mark for Review
(1) Points
True
False (*)
Incorrect Incorrect. Refer to Section 9 Lesson 4.
14. When mapping supertypes, relationships at the supertype level transform as usual. Relationships at the subtype level are implemented as foreign keys, but the foreign key columns all become optional. True or False? Mark for Review
(1) Points
True (*)
False
Correct Correct
15. Which of the following is a valid reason for considering a Subtype Implementation? Mark for Review
(1) Points
Business functionality, business rules, access paths, and frequency of access are all very different between the subtypes. (*)
The resulting table will reside in a single database and be used by just ONE user.
The common access paths for the supertypes are different.
Most of the relationships are at the supertype level.
Incorrect Incorrect. Refer to Section 9 Lesson 4.
Previous Page 3 of 3 Summary
Test: Section 9 Quiz
Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.
Section 9 Quiz
(Answer all questions in this section)
1. When mapping supertypes, relationships at the supertype level transform as usual. Relationships at subtype level are implemented as foreign keys, but the foreign key columns all become mandatory. True or False? Mark for Review
(1) Points
True
False (*)
Correct Correct
2. When mapping supertypes, relationships at the supertype level transform as usual. Relationships at the subtype level are implemented as foreign keys, but the foreign key columns all become optional. True or False? Mark for Review
(1) Points
True (*)
False
Correct Correct
3. An "Arc Implementation" can be done just like any other Relationship - you simply add the required Foreign Keys. True or False? Mark for Review
(1) Points
True
False (*)
Correct Correct
4. An Arc is transformed to the physical model by adding a foeign Key for every relationship in the Arc. True or False? Mark for Review
(1) Points
True (*)
False
Correct Correct
5. Relationships on an ERD can only be transformed into UIDs in the physical model? True or False? Mark for Review
(1) Points
True
False (*)
Incorrect Incorrect. Refer to Section 9 Lesson 3.
Page 1 of 3 Next Summary
Test: Section 9 Quiz
Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.
Section 9 Quiz
(Answer all questions in this section)
6. One-to-One relationships are transformed into Foreign Keys in the tables created at either end of that relationship. True or False? Mark for Review
(1) Points
True
False (*)
Correct Correct
7. A barrred Relationship will result in a Foreign Key column that also is part of: Mark for Review
(1) Points
The Primary Key (*)
The Check Constraint
The Column Name
The Table Name
Correct Correct
8. The explanation below is an example of which constraint type?
If the value in the balance column of the ACCOUNTS table is below 100, we must send a letter to the account owner which will require extra programming to enforce. Mark for Review
(1) Points
Referential integrity
User-defined integrity (*)
Entity integrity
Column integrity
Correct Correct
9. The explanation below is an example of which constraint type?
A column must contain only values consistent with the defined data format of the column Mark for Review
(1) Points
Entity integrity
Referential integrity
User-defined integrity
Column integrity (*)
Correct Correct
10. The explanation below is an example of which constraint type?
A primary key must be unique, and no part of the primary key can be null. Mark for Review
(1) Points
Entity integrity (*)
Column integrity
User-defined integrity
Referential integrity
Incorrect Incorrect. Refer to Section 9 Lesson 1.
Previous Page 2 of 3 Next Summary
Test: Section 9 Quiz
Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.
Section 9 Quiz
(Answer all questions in this section)
11. A foreign key always refers to a primary key in the same table. True or False? Mark for Review
(1) Points
True
False (*)
Correct Correct
12. The conceptual model is transformed into a physical model. The physical implementation will be a relational database. True or False? Mark for Review
(1) Points
True (*)
False
Correct Correct
13. In a physical data model, a relationship is represented as a combination of: (Choose Two) Mark for Review
(1) Points
(Choose all correct answers)
Check Constraint or Unique Key
Foreign Key (*)
Column
Primary Key or Unique Key (*)
Correct Correct
14. In a physical data model, an attribute becomes a _____________. Mark for Review
(1) Points
Foreign Key
Constraint
Table
Column (*)
Correct Correct
15. In an Oracle database, why would 1_TABLE not work as a table name? Mark for Review
(1) Points
There is no problem here. You can create a table called 1_TABLE.
TABLE is a reserved word.
The database does not understand all capital letters.
Object names must not start with a number. They must begin with a letter. (*)
Incorrect Incorrect. Refer to Section 9 Lesson 2.
Previous Page 3 of 3 Summary
Test: Section 9 Quiz
Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.
Section 9 Quiz
(Answer all questions in this section)
1. The explanation below is an example of which constraint type?
The value in the dept_no column of the EMPLOYEES table must match a value in the dept_no column in the DEPARTMENTS table. Mark for Review
(1) Points
Column integrity
User-defined integrity
Referential integrity (*)
Entity integrity
Incorrect Incorrect. Refer to Section 9 Lesson 1.
2. The explanation below is an example of which constraint type?
If the value in the balance column of the ACCOUNTS table is below 100, we must send a letter to the account owner which will require extra programming to enforce. Mark for Review
(1) Points
User-defined integrity (*)
Referential integrity
Column integrity
Entity integrity
Correct Correct
3. Foreign keys must be null. True or False? Mark for Review
(1) Points
True
False (*)
Incorrect Incorrect. Refer to Section 9 Lesson 1.
4. Identify all of the correct statements that complete this sentence: A primary key is: (Choose Three) Mark for Review
(1) Points
(Choose all correct answers)
A set of columns and keys in a single table that uniquely identifies each row in a single table (*)
Only one column that cannot be null
A single column that uniquely identifies each row in a table (*)
A set of columns that uniquely identifies each row in a table (*)
Correct Correct
5. One-to-Many Optional to Mandatory becomes a _______________ on the Master table. Mark for Review
(1) Points
Primary Key
Optional Foreign Key (*)
Mandatory Foreign Key
Unique Key
Correct Correct
Page 1 of 3 Next Summary
Test: Section 9 Quiz
Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.
Section 9 Quiz
(Answer all questions in this section)
6. A barrred Relationship will result in a Foreign Key column that also is part of: Mark for Review
(1) Points
The Column Name
The Table Name
The Primary Key (*)
The Check Constraint
Correct Correct
7. Two entities A and B have an optional (A) to Mandatory (B) One-to-One relationship. When they are transformed, the Foreign Key(s) is placed on: Mark for Review
(1) Points
The table B (*)
Both tables A and B get a new column and a Foreign Key.
Nowhere, One-to-One relationships are not transformed.
The table A
Incorrect Incorrect. Refer to Section 9 Lesson 3.
8. To resolve a many to many relationship in a physical model you create a(n) ___________________? Mark for Review
(1) Points
Intersection table (*)
Unique key constraints
Two tables with Foreign key constraints between them
Intersection entity
Correct Correct
9. When mapping supertypes, relationships at the supertype level transform as usual. Relationships at subtype level are implemented as foreign keys, but the foreign key columns all become mandatory. True or False? Mark for Review
(1) Points
True
False (*)
Correct Correct
10. The "Arc Implementation" is a synonym for what type of implementation? Mark for Review
(1) Points
Subtype Implementation
Supertype and Subtype Implementation (*)
Supertype Implementation
Cascade Implementation
Incorrect Incorrect. Refer to Section 9 Lesson 4.
Previous Page 2 of 3 Next Summary
Test: Section 9 Quiz
Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.
Section 9 Quiz
(Answer all questions in this section)
11. An "Arc Implementation" can be done just like any other Relationship - you simply add the required Foreign Keys. True or False? Mark for Review
(1) Points
True
False (*)
Correct Correct
12. In an Oracle database, why would 1_TABLE not work as a table name? Mark for Review
(1) Points
TABLE is a reserved word.
There is no problem here. You can create a table called 1_TABLE.
Object names must not start with a number. They must begin with a letter. (*)
The database does not understand all capital letters.
Correct Correct
13. In a physical data model, a relationship is represented as a: Mark for Review
(1) Points
Foreign Key (*)
Unique Identifier
Primary Key
Column
Correct Correct
14. In an Oracle database, why would the following table name not be allowed 'EMPLOYEE JOBS'? Mark for Review
(1) Points
EMPLOYEE is a reserved word
The database does not understand all capital letters
JOBS is a reserved word
You cannot have spaces between words in a table name (*)
Incorrect Incorrect. Refer to Section 9 Lesson 2.
15. The transformation from an ER diagram to a physical design involves changing terminology. Entities in the ER diagram become __________ : Mark for Review
(1) Points
Foreign Keys
Tables (*)
Columns
Unique Keys
Correct Correct
Previous Page 3 of 3 Summary
Test: Section 9 Quiz
Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.
Section 9 Quiz
(Answer all questions in this section)
1. In an Oracle database, why would 1_TABLE not work as a table name? Mark for Review
(1) Points
TABLE is a reserved word.
Object names must not start with a number. They must begin with a letter. (*)
There is no problem here. You can create a table called 1_TABLE.
The database does not understand all capital letters.
Correct Correct
2. In a physical data model, an entity becomes a _____________. Mark for Review
(1) Points
Attribute
Table (*)
Column
Constraint
Incorrect Incorrect. Refer to Section 9 Lesson 2.
3. The conceptual model is transformed into a physical model. The physical implementation will be a relational database. True or False? Mark for Review
(1) Points
True (*)
False
Correct Correct
4. In a physical data model, an attribute becomes a _____________. Mark for Review
(1) Points
Constraint
Table
Column (*)
Foreign Key
Correct Correct
5. An "Arc Implementation" can be done just like any other Relationship - you simply add the required Foreign Keys. True or False? Mark for Review
(1) Points
True
False (*)
Correct Correct
Page 1 of 3 Next Summary
Test: Section 9 Quiz
Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.
Section 9 Quiz
(Answer all questions in this section)
6. When translating an arc relationship to a physical design, you must turn the arc relationships into foreign keys. What additional step must you take with the created foreign keys to ensure the exclusivity principle of arc relationships? (Assume that you are implementing an Exclusive Design) (Choose Two) Mark for Review
(1) Points
(Choose all correct answers)
Make all relationships mandatory
Make all relationships optional (*)
Create an additional check constraint to verify that one foreign key is populated and the others are not (*)
All the above
Correct Correct
7. When mapping supertypes, relationships at the supertype level transform as usual. Relationships at the subtype level are implemented as foreign keys, but the foreign key columns all become optional. True or False? Mark for Review
(1) Points
True (*)
False
Correct Correct
8. A barrred Relationship will result in a Foreign Key column that also is part of: Mark for Review
(1) Points
The Primary Key (*)
The Check Constraint
The Table Name
The Column Name
Correct Correct
9. The Oracle Database can implement a many to many relationship. You simply create two foreign keys between the two tables. True or False? Mark for Review
(1) Points
True
False (*)
Correct Correct
10. One-to-One relationships are transformed into Foreign Keys in the tables created at either end of that relationship. True or False? Mark for Review
(1) Points
True
False (*)
Correct Correct
Previous Page 2 of 3 Next Summary
Test: Section 9 Quiz
Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.
Section 9 Quiz
(Answer all questions in this section)
11. Two entities A and B have an optional (A) to Mandatory (B) One-to-One relationship. When they are transformed, the Foreign Key(s) is placed on: Mark for Review
(1) Points
Nowhere, One-to-One relationships are not transformed.
The table B (*)
Both tables A and B get a new column and a Foreign Key.
The table A
Correct Correct
12. Foreign keys cannot be null when Mark for Review
(1) Points
It refers to the same table
It contains three or more columns
It is part of a primary key (*)
It refers to another table
Correct Correct
13. The explanation below is an example of which constraint type?
A column must contain only values consistent with the defined data format of the column Mark for Review
(1) Points
Column integrity (*)
Referential integrity
Entity integrity
User-defined integrity
Correct Correct
14. The explanation below is an example of which constraint type?
A primary key must be unique, and no part of the primary key can be null. Mark for Review
(1) Points
User-defined integrity
Column integrity
Entity integrity (*)
Referential integrity
Incorrect Incorrect. Refer to Section 9 Lesson 1.
15. Identify all of the incorrect statements that complete this sentence: A primary key is...(Choose three) Mark for Review
(1) Points
(Choose all correct answers)
Only one column that must be null. (*)
A set of columns in one table that uniquely identifies each row in another table. (*)
One or more columns in a table that uniquely identifies each row in that table.
A single column that uniquely identifies each column in a table. (*)
Correct Correct
Previous Page 3 of 3 Summary
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